9x^2-64x+88=0

Solution for 9x^2-64x+88=0 equation:

9x^2-64x+88=0

a = 9; b = -64; c = +88;
Δ = b2-4ac
Δ = -642-4·9·88
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-4\sqrt{58}}{2*9}=\frac{64-4\sqrt{58}}{18}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+4\sqrt{58}}{2*9}=\frac{64+4\sqrt{58}}{18}
$